[gtkada] how to print a value with 16 bit precision
Damien Carbonne
aetdcarbonne at free.fr
Thu Jun 12 07:08:39 CEST 2008
Hi,
You are simply using default parameters of Put here:
procedure Put
(Item : Num;
Fore : Field := Default_Fore;
Aft : Field := Default_Aft;
Exp : Field := Default_Exp);
and Default_Aft is defined like that :
Default_Aft : Field := Num'Digits - 1;
As Long_Float has 15 digits, that explains the 14 printed ones.
So you need to set Aft to the right value.
It could be like that:
Put (Foo) -> Put (Foo, Aft => 16);
Damien
nabh4u a écrit :
> Hello everyone,
>
> Gurus i need help. I am new to Ada programming. It is very urgent, please
> help me. i have to submit this by tomorrow. I have a small project where i
> compute the machine epsilon and i have to print the value with a 16 bit
> precision. I have tried long_float and i am getting 14 bit precision but i
> want a 16 bit precision. i have also tried to use type but was not
> successful.
>
> my code is:
>
> with Ada.Text_IO,Ada.Integer_Text_IO,Ada.Long_Float_Text_IO;
> use Ada.Text_IO,Ada.Integer_Text_IO,Ada.Long_Float_Text_IO;
> Procedure Eps is
> eps:Long_Float := 1.0;
> epsp1:Long_Float;
> pass:Integer := 0;
> cnt:Long_Float := 1.0;
> Begin
> New_Line(1);
> Put("*** Computing Machine Epsilon using Ada Language ***");
> New_Line(2);
> epsp1 := eps + 1.0;
> Put(" Pass ");
> Put(" ");
> Put(" Machine Epsilon Value ");
> New_Line(2);
> while(epsp1 > cnt) loop
> pass := pass + 1;
> eps := 0.5 * eps;
> epsp1 := eps + 1.0;
> Put(pass);
> Put(" ");
> Put(eps);
> New_Line;
> end loop;
> New_Line;
> Put("Final Eps Value : ");
> Put(eps);
> New_Line;
> Put("The Value of 1+eps+eps+eps+eps+eps+eps is : ");
> Put(cnt + eps + eps + eps + eps + eps + eps);
> New_Line;
> Put("The Value of 1+(eps+eps+eps+eps+eps+eps) is : ");
> Put(cnt + (eps + eps + eps + eps + eps + eps));
> New_Line(2);
> End Eps;
>
>
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